Question

A charge of 20 μc flows across a section of a conductor in 4 milliseconds. Calculate the
current.

Answer 1

Explanation:

I = Q/t

I = ( 20 * 10^-6)/0.004

I = (20 * 10^-6)/(4 * 10^-3)

I = 5 * 10^-3 A

I = 0.005 A

Answer 2

The amount of current that flows across a section of a conductor is 5 milliampere ( mA ).

Given: A charge of 20 μC flows across a section of a conductor in 4 milliseconds.

To Find: The amount of current that flows across a section of a conductor.

Solution:

We know that the current flowing through a conductor can be calculated by the formula,

                    I = Q / t                                                                  ...(1)

Where I = current flowing, Q = magnitude of charge, and t = time taken.

Coming to the numerical, we are given;

The magnitude of charge (Q) flowing = 20 μC = 20 × 10^-6 C

The time taken (t) = 4 milliseconds = 4 × 10^-3 seconds

Putting the respective values in (1), we can find the amount of current;

                       I = Q / t    

                   ⇒ I = ( 20 × 10^-6 ) / ( 4 × 10^-3 )

                   ⇒ I = 5 × 10^-3 A

                          = 5 mA

Hence, the amount of current that flows across a section of a conductor is 5 milliampere ( mA ).

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