Question

A charge of 200 C flows through a conductor for 6 min and 40 s. Find the magnitude of current flowing through conductor.​

Answer 1

Given:-

• Charge ,Q = 200 C

• Time taken ,t = 6min 40s = 60×6 +40 = 400s

To Find:-

• Magnitude of Current,I

Solution:-

As we know that current is defined as the flow of charge at per unit time.

• I = Q/t

Substitute the value we get

→ I = 200/400

→ I = 2/4

→ I = 1/2

→ I = 0.5 A

Therefore, the magnitude of current flowing through the conductor is 0.5 Ampere.

Additional Information!!

•Potential Difference: The potential difference between two point in an electric circuit carrying some current as the work done to move a unit charge from one point to the other.

Potential difference = Work done /Charge.

• V = W/Q

here

V is the potential difference

W is the work done

Q is the charge

• SI unit of electric potential energy is volt (V).

• 1 volt : The potential difference between two points in a current carrying conductor when one joule of work is done to move a charge of one coulomb from one point to other.

1 Volt = 1Joule/1Coulomb

Answer 2

Given:

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• Q = 200 C
• t = 6 min + 40 s

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where Q means Charge and t means Time.

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To find:

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Magnitude of current flowing through the conductor.

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Solution:

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We know that,

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I = Q/t

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where I is electric current, Q is charge and t is time.

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Now substitute the known values.

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I = Q/T

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$= \frac{200 \: C}{400 \: s}$

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= 0.5 A.

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Thus, magnitude of current flowing through conductor is 0.5 A.

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Know more:

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What is electric current?

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The rate of flow of charge from a body at a higher potential to a body at a lower potential is called electric current.

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If Q units charge flows through a conductor in time travel t, such that I is electric current then

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I = Q/t

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Thus, mathematically electric current is the ratio of the charge to the time in which charge flows.