A charge of 200 C flows through a conductor for 6 min and 40 s. Find the magnitude of current flowing through conductor.
Answers
Given:-
- Charge ,Q = 200 C
- Time taken ,t = 6min 40s = 60×6 +40 = 400s
To Find:-
- Magnitude of Current,I
Solution:-
As we know that current is defined as the flow of charge at per unit time.
• I = Q/t
Substitute the value we get
→ I = 200/400
→ I = 2/4
→ I = 1/2
→ I = 0.5 A
Therefore, the magnitude of current flowing through the conductor is 0.5 Ampere.
Additional Information!!
•Potential Difference: The potential difference between two point in an electric circuit carrying some current as the work done to move a unit charge from one point to the other.
Potential difference = Work done /Charge.
• V = W/Q
here
V is the potential difference
W is the work done
Q is the charge
• SI unit of electric potential energy is volt (V).
• 1 volt : The potential difference between two points in a current carrying conductor when one joule of work is done to move a charge of one coulomb from one point to other.
1 Volt = 1Joule/1Coulomb
Given:
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- Q = 200 C
- t = 6 min + 40 s
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where Q means Charge and t means Time.
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To find:
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Magnitude of current flowing through the conductor.
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Solution:
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We know that,
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I = Q/t
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where I is electric current, Q is charge and t is time.
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Now substitute the known values.
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I = Q/T
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= 0.5 A.
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Thus, magnitude of current flowing through conductor is 0.5 A.
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Know more:
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What is electric current?
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The rate of flow of charge from a body at a higher potential to a body at a lower potential is called electric current.
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If Q units charge flows through a conductor in time travel t, such that I is electric current then
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I = Q/t
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Thus, mathematically electric current is the ratio of the charge to the time in which charge flows.