Question

a charge of 200 coulomb flows through the filament of electric bulb of resistance 20 ohm for 25 seconds calculate potential difference across the bulb​

Answer 1

Potential Difference = 160 V

Explanation:

Given,Charge on bulb = 200C, Resistance = 20 ohm,Time = 25 sec

We know that,

I=$\frac{Q}{t}$

=$\frac{200}{25}$

= 8 A

Now,By Ohm's law

V= IR

V= $8\times 20$

 = 160 V

Hence,Potential Difference = 160 V

Answer 2

Answer:

THE POTENTIAL DIFFERENCE ACROSS THE BULB IS 160 V

Explanation:

To answer this question we need to understand the concepts of

OHM'S LAW: This states that the potential difference across a conductor is directly proportional to the current flowing through it provided the temperature and other physical conditions remain constant.Proportionality constant is the resistance.

CURRENT: It is the rate of flow of charge

GIVEN: Charge=200 C , Resistance= 25 Ohm , time= 25 seconds

TO FIND : V=?

CURRENT I=$\frac{CHARGE}{TIME}$

I=$\frac{200}{25}$=8 A

ACCORDING TO OHM'S LAW

V=IR

V=8×20=160 V