Question

A charge of 25C is moved from infinity to two
points A and B in an electric field. The work
done to move it to A is 10 J and B is 2.5 J. The
potential difference between the points A and B
IS
1) 1.0 V 2) 2.5 V 3) 0.40 V 4) 0.1 V​

Answer 1

Answer:

Option 3

Explanation:

Q=5C

W(a)=20J

V(a)=W/Q=20/5=4V

W(b)=32J

V(b)=W/Q=32/5=6.4V

Potential difference across A and B=V(b)-V(a)

V=6.4V-4V=2.4V

Hence,Option 3 is correct.