Question

A charge of 2c is in a field of intensity 2N/C, the force on the charge is:

Answer 1

Given ,

Charge (q) = 2 C

Electric field (E) = 2 N/C

We know that ,

The force per unit charge is called electric field

$\boxed{ \tt{E = \frac{f}{q}} }$

Thus ,

$\tt \mapsto 2 = \frac{f}{2}$

$\tt \mapsto f = 2 \times 2$

$\tt \mapsto f = 4 \: \: newton$

Therefore , the force on the charge is 4 N

Answer 2

Answer:

Hence, the force on the charge is $4N$.

Explanation:

Concept:

The properties of the electric force for charges at rest are as follows: Charges that are similar repel each other, while charges that are dissimilar attract each other.

Given:

A charge $(q) = 2 C$

Electric field $(E) = \frac{2N}{C}$

To find:

We have to find the force on the charge.

Solution:

As we know that,

The force per unit charge is called electric field and the formula is,

$E=\frac{F}{q}$

$F=E*q\\F=\frac{2N}{C} *2C$

$F=4N$

Thus, the force on the charge is $4N$.

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