Question

A charge of 2C is moved in an electric field from infinity to two points A and B. If the work done in bringing
it to point B is 16j. calculate the potential difference between points A and B.​

Answer 1

Answer:

Work done = 10 joule

Charge = 2 coulomb

Potential of point A VA = 10 J / 2C = 5V

Given work done = 20 Joule

Charge = 2 coulomb

Potential of point A VB = 20 J / 2C = 10V

Potential differences between two point A and B is

V = VB - VA

= 10V - 5V = 5V

Work done directly from A to B.

Work done = Potential difference × charge

= 5V × 2C

10 Joule.