Question

A charge of 2C moves between two plates maintained at a potential difference of 1V. What ia the energy acquired by the charge ?

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Answer 1

SOLUTION :-

We know that the formula of Potential difference, V= W/Q ————(i)

Given that the Energy needed to move a charge of Q = 2 Coulomb between two plates where the electric potential is V

Hence the formula in equation (i) can be rewritten as W=QV ————(ii)

As per the given conditionsQ = 2 C, Potential difference V = 1V.

Putting theknownvalues in equation (i),

Energy acquired by the charge,

W = QV

= 2 x 1

= 2 Joule

Energy acquired by the charge= 2 Joule

Answer 2

Given that ,

Charge (q) = 2 C

Potential difference (v) = 1 V

As we know that ,

The work done to move a unit charge from one point to another point is called potential difference

It is denoted by " v "

$\sf \underline{ \fbox{Potential \: difference \: (v) = \frac{w}{q} }}$

The SI unit of potential difference is " volt "

Thus ,

$\Rightarrow \sf1 = \frac{w}{2} \\ \\\Rightarrow \sf w = 2 \: \: joule$

$\therefore \bold{ \sf \underline{The \: energy \: is \: 2 \: joule \: }}$