a charge of 3.2×10^-19 C enter the magnetic field of intensity 3wb/m^2 with velocity 10^6m/s and at an angle od 60 degree . calculate the force
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calculate the force of Acharge
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8.30*10^-13 N
Explanation:
Magnetic Force formula
F= qVB sin theta
F= (3.2*10^-19)*(10^6)*(3)*sin 60°
F= (3.2*10^-19)*(10^6)*(3)*(√3/2)
F= 8.30*10^-13 N
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