a charge of 3000C flows through a electric circuit in 2.5 hours.Calculate the magnitude of the current flowing through the circuit
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Answered by
1
Answer:
Hey mate here is answer...
Charge = 5000 C
time = 2.5 hr = 9000 s
I = Q÷t
= 5000÷9000
= 0.56 A
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Answered by
0
Answer:
3000/9000=0.33C
Explanation:
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