Question

A charge of 4 C is moved across two points A and B. If the the two
points have a potential of +5 V and -5 V respectively, then what is the
amount of work done in moving the charge between the two points. If
the time taken to move the charge is 5 s then, what is the power?​

Answer 1

Answer:

Q= 4C

V1= +5V, V2= -5V

W1= Q.V1= 4×5 J = 20J

W2= Q.V2= 4×-5 J= -20J

Time taken is 5 sec

so, power= 20/5W, -20/5W

= 4W, -4W