Question

A charge of 4 uC is moved from a point of -10 V to a
point where potential is 30 V. The work done in doing
so is
4C का एक आवेश-10V के एक बिन्दु से उस बिन्दु जहाँ विभव
30V है, तक गति करता है। ऐसा करने में किया गया कार्य है
10J
100x107J
C
160x10-6J
D
10x103J​

Answer 1

Answer:

$\boxed{\orange{\sf Work = 1.6\times 10^{-4} J }}$

Explanation:

Given that , a charge of $\sf 4\mu C$ is from a point of -10V to a point where the potential is 30V . We need to find the work done.

And we know that , the Electrical Potential is defined as ,

• The amount of work done in bringing a unit positive charge from infinity to a certain point in an electric field is called Potential difference.

$\sf\longrightarrow Voltage =\dfrac{Work}{Charge}\\\\\sf\longrightarrow (V_A- V_B) = =\dfrac{Work}{Charge}\\\\\sf\longrightarrow 30V - (-10V) =\dfrac{Work}{4\times 10^{-6} C}\\\\\sf\longrightarrow 30V + 10V =\dfrac{Work}{4\times 10^{-6} C}\\\\\sf\longrightarrow 40V =\dfrac{Work}{4\times 10^{-6} C}\\\\\sf\longrightarrow Work =40\times 4\times 10^{-6} \\\\\sf\longrightarrow \boxed{\sf\pink{ Work = 1.6\times 10^{-4} J }}$