Question

a charge of 400C flows through a conductor for 1.3 minutes and 20 sec findto the magnitude of thea current flowimg through thea conductor.

Answer 1

I = charge/time
I= 400/98
I=4.0816A

Answer 2

Given,

The charge flowing through a conductor = 400 C

The time is also given = 1.3 minute and 20 seconds;

Converting the complete time into seconds i.e., 1 minute = 60 seconds;

0.3 minute = 60 x 0.3= 18 seconds;

20 seconds gives 98 seconds.

Now we know the formula for current is charge per unit time.

That is

$I=\frac { Q }{ T }$

So current I here will be = 400/98 = 4.08 A.