a charge of +5 microc experiences a force of 1mN in an electric field.what is the magnitude of the electric field intensity at the position of the charge
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the formula for force is also given by F =qE
where q = charge
E = electric field
F= 1mN= 10^-3
q = 5 μC = 5* 10^-6
E = F/q
= (10^-3)/ (5*10^-6)
= 200 V/m
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