a charge of 5 microcoulomb and 4 microcoulomb are placed at a distance of 3m in air , the coulumbs force between them is
a. 20N
b. 2N
3. 0.2N
d. 0.02N
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Answer:
d) 0.02N
Explanation:
F=kq1q2/r^2
= 9 x 10^9 * 5 * 10^-6 * 4 * 10^-6/3^3
= 20 * 10^-3
F= 0.02N
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