Physics, asked by ayesha2001, 4 months ago

a charge of 5 microcoulomb and 4 microcoulomb are placed at a distance of 3m in air , the coulumbs force between them is
a. 20N
b. 2N
3. 0.2N
d. 0.02N​

Answers

Answered by profsandeep
1

Answer:

d) 0.02N

Explanation:

F=kq1q2/r^2

  = 9 x 10^9 * 5 * 10^-6 * 4 * 10^-6/3^3

 = 20 * 10^-3

F= 0.02N

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