Question

A charge of 500 coloumb flows through a conductor for 2 hour and 30 minutes find themagnitude of current flowing through the conductor

Answer 1

Answer: by using formula for current

Answer 2

AnswEr :

From the Question,

• Charge (Q) = 500 C

• Time taken (t) = 2hr 30 min = 150 min = (150 × 60) s = 9000 s

To finD

Current flowing in the conductor

Current

• The rate of flow of charges is known as Current

• It is denoted by Ampere (A)

Mathematically,

$\star \ \boxed{\sf I = \dfrac{Q}{t}}$

Putting the values,

$\implies \: \sf \: l = \dfrac{500}{9000} \\ \\ \implies \: \sf \: l = \dfrac{5}{90} \\ \\ \implies \: \sf \: l = \dfrac{1}{18} \\ \\ \implies \: \boxed{ \boxed{ \sf \: l = 56 \times {10}^{ - 2} A}}$

The current flowing through the conductor is of the magnitude 56 × 10^-2 A