Question

A charge of 5000 coloumb flows through a conductor for 2 hour and 30 minutes find themagnitude of current flowing through the conductor

Answer 1

Answer:

CURRENT ( i ) = 0.55 Ampere

Explanation:

★ CURRENT ELECTRICITY ★

GIVEN ;

★ CHARGE ( Q ) = 5000 C

★ TIME ( T ) = 2hr 30 min.

» CURRENT ( i ) = ???

_________WE KNOW THAT ; _______

★ CURRENT ( i ) = CHARGE (Q) / TIME (T)

» i = Q / T

» i = 5000 / 2 hour 30 min.

» i = 5000 / 150 min.

» i = 5000 / 150 × 60 seconds

» i = 5000 / 9000

★ » i = 0.55 Ampere « ★

________________________________________

ANSWER :- Current flowing in Time " t " at charge of 5000 Coulomb is ;

★ i = 0.55 Ampere ★

Answer 2

Answer:

Charge, q = 5000 C

Time, t = 2 hr 30 m = 120 + 30 = 150 m × 60 = 9000 seconds.

Magnitude of current, I = q/t

I = 5000 C / 9000 s = 0.55 A

I = 0.55 A