Question

A charge of 50C is moved from infinity to two points A and B in an electric field. The work done to do so up-to A and B is 20J and 30J respectively. What is the potential difference between points A and B?​

Answer 1

Answer:

Given :

Charge of particle , Q = 50 C .

To Find :

The potential difference between point a and b .

Solution :

We know , potential energy is given by change in work done by charge on particle .

\begin{gathered}V=\dfrac{Difference\ in\ work\ Done}{Charge}\\\\V=\dfrac{W_f-W_i}{Q}\\\\V=\dfrac{25-20}{50}\ V\\\\V=0.1 \ V\end{gathered}

V=

Charge

Difference in work Done

V=

Q

W

f

−W

i

V=

50

25−20

V

V=0.1 V

Therefore , potential difference between point a and b is 0.1 V .

Learn More :

Electrostatics

Answer 2

hope that it will help u