Question

A charge of 6.25 in an electric field is acted upon by a force 2.5 N.
The potential gradient at this point is​

Answer 1

Given:

Charge in the electric field =  6.25

Force = 2.5 N.

To Find:

The potential gradient at this point

Solution:

Potential gradient at a point is given by -

dV/dr = E = F ( The force on the charge) /Q ( The charge)

Therefore,

dV/dr = 2.5 / 6.25 × 10`6

= 4 × 10`5

Answer: The potential gradient at the said point is 4 × 10`5 N/c