Question

A charge of 75 C is brought from infinity to a given point in an electric field when the amount of work done is 12.5 j calculate the electric potential at that point​

Answer 1

Answer:

0.16 or 1/6

Explanation:

Work done = potential difference*charge

12.5 = p*75

12.5/75 = p = 1/6 = 0.16

Answer 2

Answer: volt = joule /coulomb

j= 12.5

Q=75

V=12.5/75

V=1/6

V=0.16

Explanation:

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