Question

A charge paricle produce an electric feild with a magnitude of 20N/C at a point that is 50 cm away from a particles .What is the magnitude of the particle charge​

Answer 1

Explanation:

don't know dear...........

Answer 2

Given:-

• Electric field produced = 20 N/ C

The distance of the charge from the point = 50 cm

we need to convert cm into m in order to do that simply divide by 100

• The distance of the charge from the point = 0.5 m

To find :-

• Magnitude of charged particle

Solution:-

The electric field produced by the charge on the point kept at a certain distance r is given by the formula ,

⟹ E = kq / r ²

here ,

• k = coulomb's  constant
• q = charge
• r = distance between the point and the charge

On rearranging ,

⟹ q = E r² / k

Now let's substitute the given values in the above equation

⟹ q = 20 x 0.25 / 9 x 10^9

⟹ q = 5 / 9 x 10^9

⟹ q = 0.55 x 10^-9

⟹ q = 0.6 nC

The magnitude of the charged particle is 0.6 nC