Question

a charge particle having charge 2 Coulomb is thrown with velocity 2i^+3j^ inside a region having E = 2j^ and magnetic field 5k^ . find the initial Lorentz force acting on the particle​

Answer 1

Answer:

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Explanation:

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Answer 2

The correct answer is F = 30i - 16j.

Given: Charge = 2C.

v = 2 î + 3 j

E = 2 j

B = 5 k (Because E and B are mutually perpendicular).

To Find: Initial Lorentz force.

Solution:

As we know,

F = q (E + V × B)  (all are in vectors)

Now, we will do the cross product of V and B.

$\left[\begin{array}{ccc}i&j&k\\2&3&0\\0&0&5\end{array}\right]$

= i (15 - 0) - j (10 - 0) + k (0 - 0)

= 15 i - 10 j

F = q (E + V × B)

= 2 (2j + 15i - 10j)

F = 30i - 16j

Hence, the Lorentz force is F = 30i - 16j.

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