Question

A charge particle having charge q and speed V is moving in XY plane in x directions. It enters in a region of uniform electric field directed in y-direction and extended upto x= 0 to x=d then what is the equation of path in terms of d .

Answer 1

A charge particle having charge q and speed v is moving xy plane in x directions. it enters in a region of uniform electric field directed in y - direction and extended upto x = 0 to x = d.

To find : The equation of path in term of d.

solution : distance covered in x direction, d = vt

⇒t = d/v .......(1)

an acceleration acting on the charge along y direction due to uniform electric field.

magnitude of acceleration, a = qE/m

distance covered in y direction, y = ut + 1/2 at²

but initial velocity along y - axis, u = 0

so, y = 1/2 (qE/m) t²

from equation (1),

y = 1/2 (qE/m)(d²/v²)

⇒y = qEd²/2mv²

Therefore the equation of path in term of d is y = qEd²/2mv²