a charge particle of charge q and mass m with I itial velocity vo from. argon along x axis and a uniform electric field along y axis,then find the angle between velocity vector of charged particle with x axis after time t from start
Answers
Answer:
What would you like to ask?
12th
Physics
Moving Charges and Magnetism
Lorentz Force
A particle of mass m and ch...
PHYSICS
avatar
Asked on January 17, 2020 by
Munny Vizhi
A particle of mass m and charge q has an initial velocity
v
=v
0
j
^
. If an electric field
E
=E
0
i
^
and magnetic field
B
=B
0
i
^
act on the particle, its speed will double after a time.
MEDIUM
Share
Study later
ANSWER
Given
V
i
=V
0
j
^
,
E
=E
0
i
^
,
B
=B
0
i
^
Now we see that the velocity is perpendicular to the magnetic field so the magnitude of velocity will not change due to magnetic field.
The magnitude of velocity will change in 'i' direction due to
E
only
acc=
mass
force
due to
E
on particle =
m
qE
0
i
^
Let us say that the speed of particle doubles after time 't'. in y direction the speed will be V
0
only in y−z plane always perpendicular to x-direction so net speed at time 't'.
(V
net
)
2
=
V in y−z plane
(V
0
)
2
+
V
x
after time tin x−direction
(
m
qE
0
t)
2
.
Also by given condition V
net
=2V
0
⇒(2V
0
)
2
=V
0
2
+(
m
qE
0
t)
2
⇒4V
0
2
−V
0
2
=(
m
qE
0
t)
2
⇒3V
0
2
=(
m
qE
0
t)
2
⇒t=
qE
0
3
V
0
m