Physics, asked by mrkwoledge9733, 1 year ago

A charge q μc is placed at the centre of a cube of a side 0.1 m, then the electric flux diverging from each face of the cube is

Answers

Answered by ishucutee
6

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Answer:-

electric \: flux =  \frac{q}{e.}  \\  \\ electric \: flux =  \frac{q}{6e.}

We divide charge by 6 Beacuse a cube has 6 face___

e. Is the permitvity of free space.

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Answered by malini5426
0

Answer:

The electric flux diverging from each face of the cube is q×10^−6/6e or (lamdaX0.1X10^-6)/6e

Explanation:

Given,

A charge q microcoloumb is placed at the centre of a cube of a side 0.1m.

Electric flux ad per Guass law is given by

Electric flux = q/e

where,

q = charge

e = permittivity of free space

  • As cube had 6 faces and charge is placed at Geometric centre ,and also as charge is additive quality same ad Flux. Charge in centre influence with 6 faces of cube ,hence 6 fluxes are possible and is given by Equation;

Electric flux = q/6e

  • As charge is given microcoloumb we need to convert it into coloumb
  • To convert it into coloumb we should multiply with 10^-6

Now we get,

Electric flux = (q x 10^-6)/6 e---------->>1

or

q=Lambda×length.

length =0.1 m

substitute q value in equation 1

  • we get,

Electric flux = (lamda × 0.1 × 10^-6)/6e

where ,

e = permittivity of free space

Hence,The electric flux diverging from each face of the cube is q×10^−6/6e or (lamdaX0.1X10^-6)/6e

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