A charge QμC is placed at the centre of a cube. what is the flux coming out from any one surface.
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flux coming out from one surface
= 1/6 ×q/€ = 1/6 ×Q×10-6/€
Explanation :
charge = Q ×10 ^-6 C
we know,
flux = charge / epsilon
= q/€
we know, a square has six faces
flux coming out from one surface of square = 1/6 ×Q×10^-6 / €
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Answered by
1
Answer:
{Q×10^(-6)}/(6 × epsilon)
Explanation:
Apply gauss law,
flux through closed surface = enclosed charge/epsilon
so, flux through cube(6-surfaces) = Q×10^(-6)/epsilon
flux through one surface = Q×10^(-6)/(6 × epsilon)
wrong
why
go and read a book to clear your doubts.
φ=1/6.Q /ξο μNm²/c.
it's a correct answer bhai
even though, I am suggesting you to go through books to clear your concepts. it will be better for you and your future.
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mujhe iska answer pta hai just kidding answer is r8
don't take it seriously
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