Physics, asked by sahil9191, 1 year ago

A charge QμC is placed at the centre of a cube. what is the flux coming out from any one surface.

#abb ki delete na ker de koi isay

Answers

Answered by beingankitaa

flux coming out from one surface

= 1/6 ×q/€ = 1/6 ×Q×10-6/€

Explanation :

charge = Q ×10 ^-6 C

we know,

flux = charge / epsilon

= q/€

we know, a square has six faces

flux coming out from one surface of square = 1/6 ×Q×10^-6 / €

sahil9191: toh tum kyu continue rekh ri hoo bhena

sahil9191: u can ignore it

sahil9191: Hahaha

beingankitaa: behes krna toh meri adat hai

sahil9191: toh change ker le na usay

beingankitaa: kyu

sahil9191: koi pit ke chala jayege

sahil9191: fir rote rote mere pass ayegi bhaiya marr diya

beingankitaa: kuch bhi

sahil9191: mat ker bhen abb message dusre bande ko problem ho ri hogi

Answered by MidA

Answer:

{Q×10^(-6)}/(6 × epsilon)

Explanation:

Apply gauss law,

flux through closed surface = enclosed charge/epsilon

so, flux through cube(6-surfaces) = Q×10^(-6)/epsilon

flux through one surface = Q×10^(-6)/(6 × epsilon)

sahil9191: wrong

MidA: why

MidA: go and read a book to clear your doubts.

sahil9191: φ=1/6.Q /ξο μNm²/c.

sahil9191: it's a correct answer bhai

MidA: even though, I am suggesting you to go through books to clear your concepts. it will be better for you and your future.

sahil9191: bhai majak majak mein pucha hai

sahil9191: mujhe iska answer pta hai just kidding answer is r8

sahil9191: don't take it seriously

Previous Question

Next Question