Question

A charge 'q' enters perpendicularly with direction of Magnetic field B with velocity 'v' .What would be force acting on this charge?​

Answer 1

$f = q(v\times b)$

$f = qvb \sin( \alpha )$

so for

$\alpha = 90 {}^{o}$

$f = qvb$

Answer 2

Explanation:

• When a charge 'q' enters perpendicularly with direction of magnetic field B with velocity 'v', it would have magnetic force.
• Th magnetic force is given by :

$F=q(v\times B)\\\\F=qvB\sin \theta$

$\theta$ is angle between v and B

If it enters perpendicularly with direction of magnetic field, then $\theta=90^{\circ}$. As a result, force is given by :

$F=qvB$

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Magnetic force

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