Physics, asked by harshchhabra6945, 1 year ago

A charge q is distributed over three concentric spherical shells of radii a, b, c (a < b < c ) such that their surface charge densities are equal to one another. The total potential at a point at distance r from their common centre, where r < a, would be :

Answers

Answered by abhi178
0

Let charge on spherical shell of radius a is Q_a

charge on spherical shell of radius a is Q_b

charge on spherical shell of radius a is Q_c

now, potential at the surface of spherical shell A , V_A=\frac{kQ_b}{a}

potential at the surface of spherical shell B , V_B=\frac{kQ_b}{a}

potential at the surface of spherical shell C , V_C=\frac{kQ_c}{c}

Let \sigma is the surface charge density of all of them.

then, charge = \sigma \textbf{area}

so, Q_a:Q_b:Q_c=a^2:b^2:c^2

so, Q_a=\frac{a^2}{a^2+b^2+c^2}q

Q_b=\frac{b^2}{a^2+b^2+c^2}q

Q_c=\frac{c^2}{a^2+b^2+c^2}q

so, total potential , V = V_A+V_B+V_C

= \frac{kq}{a^2+b^2+c^2}(a+b+c) This is required answer.

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