Question

A charge Q is divided into two parts and then they are placed at fixed distance The force between the two charge is alway maximum when the charge are..​

Answer 1

Answer:

F=

r

2

KQ

1

Q

2

⟹F=

r

2

KQ

1

(Q−Q

1

)

Differentiating both sides with respect to Q

1

−

r

2

K

(q−2Q

1

)=

dQ

1

dF

For, force to be maximum,

dQ

1

dF

=0

⟹Q−2Q

1

=0

⟹Q

1

=

2

Q

Q

2

=Q−Q

1

=

2

Q