Question

A charge q is divided into two such parts, so that force between them when placed at some separation is maximum.find their values.

Answer 1

HERE IS YOURS SOLUTION;

◆ Let parts are sepereted at a distance of d

so repulsion force F= k q(Q-q)/d2

◆ Here Q and d are constant so for maximum force differentiate the force w.r.t q.

 dF/dq = k/d2 [Q -2q]

◆ For maximum force dF/dq=0

=> Q-2q=0

=> Q/q =2

HOPE IT HELPS