Physics, asked by abhay385abhay, 7 months ago

A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, the electric flux through the surface
(a) will be reduced to half
(b) will be doubled
(c) will remain same
(d) will be quadrupled​

Answers

Answered by farhatkhalilshaikh
2

Answer:

pls comment if wrong

Explanation:

If the radius of the Gaussian surface is doubled, the outward electric flux will remain the same. This is because electric flux depends only on the charge enclosed by the surface.

Answered by itskashifakhtar
1

Answer:

A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, the electric flux through the surface will be doubled

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