Question

A charge Q is kept at the corner of a
cube. Electric flux passing through one
of those faces not touching that charge
is?​

Answer 1

Answer:

Charge q is placed at the corner of a cube. What is the flux through one face of a cube?

q/(24*epsilon)

Imagine there were 8 cubes and the charge was placed at the common corner.

By Gauss’ law flux would be q/epsilon

Since all 8 cubes are identical flux through each cube is q/(8*epsilon)

Now in the cube the 3 faces which share the corner at which cube is kept would have no flux through it (Field and area would be perpendicular so dot product is zero). In the remaining 3 faces, the flux is distributed evenly hence total flux = q/(24*epsilon)

Explanation:

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