Question

A charge q is moved from A to C along the path ABC as shown in figure. The work done in moving charge from A to C is a) qEa b) qE √a²+ b² c) qEb d) qEb/√2

Answer 1

• General Expression of work is $\rm W = F \times d\times \cos(\theta)$.

Total Work will be :

$\sf W_{Total} = W_{AB} + W_{BC}$

$\sf \implies W_{Total} = \{qE \times a \times \cos( {90}^{ \circ} ) \} + \{ qE \times b \sec( {45}^{ \circ} ) \times \cos( {45}^{ \circ} ) \}$

$\sf \implies W_{Total} = \{qE \times a \times 0\} + \{ qE \times b \sqrt{2} \times \dfrac{1}{ \sqrt{2} } \}$

$\sf \implies W_{Total} = 0 + \{ qE \times b \sqrt{2} \times \dfrac{1}{ \sqrt{2} } \}$

$\sf \implies W_{Total} = qE b$

Total Work done is qEb (Option C) ✔️