Question

A charge q is placed at a distance of 4r above the centre of a disc of radius r

Answer 1

Answer:

Explanation:

Hey,

Your question seems incomplete..

Here, A charge q is placed at a distance of 4r above the centre of a disc of radius r.

=>  If the magnitude flux through the disc is Ф. A hemisphere shell of radius R is placed over the disc such that it forms a closed surface. then Find the flux through the curved surface.

So, Фshell + Фdisc = 0

and According to question, No charge is found inside the closed surface.

Thus, Фshell = -Фdisc = -Ф

Therefore, the flux through the curved surface is -Ф.

 

Answer 2

Answer:

-  Ф

Explanation:

since there is no charge enclosed . hence net flux = 0

flux due to disc + flux due to hemisphere = 0