A charge q is placed at each of the opposite corners of a square.a charge q is placed at each of the other two corners .if the net electrical force on q is zero ,then q/q equals
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Suppose, we have a square ABCD.
Let Charges Q be placed at A and C and q at B and D. Consider the forces at C. For C to be in equilibrium, it is necessary that Q and q should have opposite signs. Further resultant of forces FDand FC should be equal in magnitude to FA.
So,
Q^2/2a = √2 (Q×q/a^2)
Q = 2√2 q
With sign,
Q = −2√2 q
Q/q = −2/√2
Let Charges Q be placed at A and C and q at B and D. Consider the forces at C. For C to be in equilibrium, it is necessary that Q and q should have opposite signs. Further resultant of forces FDand FC should be equal in magnitude to FA.
So,
Q^2/2a = √2 (Q×q/a^2)
Q = 2√2 q
With sign,
Q = −2√2 q
Q/q = −2/√2
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30
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