A charge q is placed at the center of a cube. How much flux wil be linked
with each face?
6Q/ Eo
O Q/3Eo
O Q/6Eo
O Q/ Eo
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Answer:
Q/€o
Explanation:
According to Gauss's law, the electric flux,
ϕ= €o /Q enclosed
Here the charge enclosed inside the cube is
Q enclosed =Q
thus, ϕ= Q/€o
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