Question

A charge q is placed at the centre of the line joining two equal charges of magnitude q. show that the system of this charges will be in equilibrium if q=-q/4

Answer 1

hope it will help you..

Answer 2

Answer:

The charges will be in equilibrium only if Q=-q/4.

Explanation:

• The net force on each charge should be zero for the system to be in equilibrium.
• Both outside charges q will exert equal and opposite forces on Q as a result of symmetry, which will cancel out.
• Regardless of the charge value, the net force on Q will always be zero.

Now we will use Columb's law.

$F_q_q=-F_Q_q$

$\frac{kq^2}{(2x)^2}=\frac{-kQq}{x^2}$        (k= Columb's constant)

$\frac{q}{4x^2}=\frac{-Q}{x^2}$

$Q=\frac{-q}{4}$

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Your question is incomplete, but most probably your full question was"A charge Q is placed at the center of the line joining two equal charges of magnitude q. Show that the system of these charges will be in equilibrium if Q=-q/4."