Question

A charge q is placed at the centre of the line joining two equal charges Q. Show that the system of three charges will be in equilibrium if q= -Q÷4 ?​

Answer 1

Answer:

Let's see the force on one Q.

F=4a2kQ2+a2kqQ

For the system to be equilibrium F=0.

4a2kQ2+a2kqQ=0

q=−4Q.

Now, we placed a third charge q at the midpoint of the line joining the two charges, i.e. at a distance of d2 from each charge Q. Here, each charge will experience a force due to the other two charges. Now, for the system to be at equilibrium, the net forces on all the three charges must be zero.

Answer 2

Explanation:

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