A charge q is placed at the centroid of an equilateral triangle. Three charges equal to Q are placed at the vertices of the triangle . The system of the four charges will be in equilibrium . if q is equal to
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∆ Distance between Unit charges q and Q can be easily taken out by the Height of Equilateral Triangle and 2:1 division due to Centroid !
∆ Vector Resultant of Electromagnetic Forces due to Q on each vertices result in a Vector which Bisects the External Angle and thus, is opposite to the Force Vector due to Charge 'q'
Hope this helps
∆ Distance between Unit charges q and Q can be easily taken out by the Height of Equilateral Triangle and 2:1 division due to Centroid !
∆ Vector Resultant of Electromagnetic Forces due to Q on each vertices result in a Vector which Bisects the External Angle and thus, is opposite to the Force Vector due to Charge 'q'
Hope this helps
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Distance between unit charges q and Q can be easily taken out by the Height of Equilateral Triangle and 2:1 di
vision due to Centrid !
Vector Resultant of Electromagnetic
Forcess due to Q on each vertices result in a
Vector which Bisects the External Angle and thus , is opposite to the Force Vector due to Charge 'q'
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