Question

A charge q is placed at the mouth of a conical flask. The flux of the electric field through the flask is

Answer 1

answer : $\frac{Q}{2\epsilon_0}$

explanation : A charge Q is placed at the mouth of conical flask. so, number of electric lines of force are shared equally in both faces as shown in figure . it means, charge enclosed inside the gaussian surface is Q/2.

now from Gaussian theorem,

electric flux through gaussian surface is given by ratio of charge enclosed inside the gaussian surface to the permittivity of medium.

e.g., electric flux through conical flask , $\phi=\frac{Q/2}{\epsilon_0}=\frac{Q}{2\epsilon_0}$

Answer 2

Answer:

Explanation:: A charge Q is placed at the mouth of conical flask. so, number of electric lines of force are shared equally in both faces as shown in figure . it means, charge enclosed inside the gaussian surface is Q/2.

now from Gaussian theorem,

electric flux through gaussian surface is given by ratio of charge enclosed inside the gaussian surface to the permittivity of medium.

e.g., electric flux through conical flask ,