Math, asked by Anonymous, 7 hours ago

A charge q is situated at the origin. Let \sf{E_A}\sf{E_B} \sf{E_C}be the electric fields at the points A(2, -3, -1), B(-1, -2, 4) and 2, -4, 1). Therefore,
\bf{Options\;:}
(a) \sf{E_A\perp E_B}
(b) no work is done in moving a test charge \sf{q_0}
(c)\sf{2\mid E_A \mid = 3 \mid E_B \mid}
(d)\sf{E_B=-E_C}
\boxed{\red{\bf{Note\;:}}} Among the given four alternatives out of which ANY NUMBER OF ALTERNATIVES (1 , 2 , 3 , 4) MAY BE CORRECT.​

Answers

Answered by manjulapadhi02
0

Answer:

situated at the origin. Let \sf{E_A}\sf{E_B} \sf{E_C}be the electric fields at the points A(2, -3, -1), B(-1, -2, 4) and 2, -4, 1). Therefore,

\bf{Options\;:}

(a) \sf{E_A\perp E_B}

(b) no work is done in moving a test charge \sf{q_0}

(c)\sf{2\mid E_A \mid = 3 \mid E_B \mid}

(d)\sf{E_B=-E_C}

\boxed{\red{\bf{Note\;:}}} Among the given four alternatives out of which ANY NUMBER OF ALTERNATIVES (1 , 2 , 3 , 4) MAY BE CORRECT.

Similar questions