A charge Q is uniformly distributed over the surface of a spherical shell
of radius R. The work done in bringing a test charge Q, from its centre to
its surface is
1 QQ
41 R
(B)
1 QQ
4 ne, 2R
(C) QQ,
EOR
(D)
Zero
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4
Answer:
answer is zero as electric field inside the shell is zero
Answered by
1
The work done in bringing a test charge Q from its Centre to surface is zero.
as the charge on the surface is equal at all points then it is called as a equipotential surface
The electric field in side the shell is zero.
the work done in bringing a charge from one point to another is equal to the potential difference between the two points .
potential difference = total work done/ total charge
V=W/Q
w = F * D
by coulombs law,
F is equal to
k= 1/ 4π∈°
F= k q1q2/ r²
hence using above the q2 inside the sphere is zero so f is zero hence the work done in bringing the charge from Centre to the surface is zero.
#SPJ2
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