Question

a charge q placed at the centre of circle of radius r. the work done in moving a charge from A to B in a semi circle is.​

Answer 1

Answer:

The work done in carrying a charge q once round a circle of radius r with a charge Q at the centre is. It is an equipotential surface. Hence, work done in carrying a charge q round the circle is zero

Answer 2

Answer: The answer to this question is-

A charge q placed at the centre of circle of radius r. the work done in moving a charge from A to B in a semi circle is.​

W = q( $V_{B} - V_{A}$) = 0 As $V_{A}$ = $V_{B}$

Explanation:

Electrostatic force is a conservative force, hence the amount of work it does in a circular motion is zero.

When the overall effort needed to move a particle between two sites is unaffected by the path the particle takes, the force is said to be conservative.

Returning to the question of whether electrostatic force is conservative, let's talk about it now.

Because it complies with and does not contradict the aforementioned criteria, the electrostatic force can be explained as being conservative. Let's use an illustration to show this.

Consider the two-charge system , where a unit positive charge, designated as "Q," is taken from location A to position B along a straight line and then from position B to position A through any other path. The labour required to transfer control along a closed path should then be equal to zero. If this is the case, it indicates that the electrostatic force is moderate.

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