Physics, asked by Hibbert977, 14 days ago

A charge q1 = 2.00 µC is located at the origin, and a charge q2 = 6.00 µC is located at (0, 3.00) m. Find the total electric potential due to these charges at the point P, whose coordinates are (4.00, 0) m.

Answers

Answered by dwivedishubh626
0

Answer:

Step 1: Potential due to q

1

to q

2

[Ref. Fig.]

From Figure distance r

2

=5m

At point A

Potential due to q

1

, V

1

=

r

1

Kq

1

=

4m

9×10

9

×(2×10

−6

C)

⇒ V

1

=4.5×10

3

Volts

Potential due to q

2

, V

2

=

r

2

Kq

2

=

5m

9×10

9

×(−6×10

−6

C)

⇒ V

2

=−10.8×10

3

Volts

Step 2: Net Potential at Point (A)

Potential is a scalar quantity

So, V

net

=V

1

+V

2

=4.5×10

3

−10.8×10

3

=−6.3×10

3

volts

V

net

=−6.3KV

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