A charge q1 = 2.00 µC is located at the origin, and a charge q2 = 6.00 µC is located at (0, 3.00) m. Find the total electric potential due to these charges at the point P, whose coordinates are (4.00, 0) m.
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Answer:
Step 1: Potential due to q
1
to q
2
[Ref. Fig.]
From Figure distance r
2
=5m
At point A
Potential due to q
1
, V
1
=
r
1
Kq
1
=
4m
9×10
9
×(2×10
−6
C)
⇒ V
1
=4.5×10
3
Volts
Potential due to q
2
, V
2
=
r
2
Kq
2
=
5m
9×10
9
×(−6×10
−6
C)
⇒ V
2
=−10.8×10
3
Volts
Step 2: Net Potential at Point (A)
Potential is a scalar quantity
So, V
net
=V
1
+V
2
=4.5×10
3
−10.8×10
3
=−6.3×10
3
volts
V
net
=−6.3KV
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