Physics, asked by senishita4164, 9 months ago

A charge situated at a distance from electric dipole in the end on position experiences a force F. If the distance of the charge is double the the force acting on the charge is what?

Answers

Answered by sourya1794
41

\sf\star\bold\red{\underline{{QUESTION:-}}}

A charge situated at a distance from electric dipole in the end on position experiences a force F. If the distance of the charge is double the the force acting on the charge is what?

\sf\star\bold\green{\underline{{SOLUTION:-}}}

Let the dipole moment be p and the charge be q placed at the distance r from the dipole.

The electric field due to the dipole at an axial point is

\sf\:E =\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{2p}{r^3}

\sf\boxed\star\pink{\underline{\underline{{Force\:on\:charge\:q\:at\:a\:distance\:r\:will\:be:-}}}}

\sf\:F = qE

\sf\:F = q\times\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{2p}{r^3}

\sf\boxed\star\orange{\underline{\underline{{If\: distance\:is\:doubled:-}}}}

Then,

\sf\implies\:F'=q\times\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{2p}{(2r)^3}

\sf\green{{\implies\:F'=\dfrac{1}{8}}}

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