Question

A charged 30 μF capacitor is connected to a 27 mH inductor. Suppose the initial charge on the capacitor is 6 mC. What is the total energy stored in the circuit initially? What is the total energy at later time?

Answer 1

Answer:

30 × 27/6 = 5 × 27 = 135mC ,...

Answer 2

Answer:

1.2 J

Explanation:

Given,

The capacitance of the capacitor, C = 30 μF

The inductance of the capacitor, L = 27 mH

initial charge on the capacitor, q = 6mC

Initial energy stored in the circuit,  

$E\ =\ \dfrac{q^2}{2C}$

    =1.2 J

Since the inductor is connected with the charged capacitor and inductor is reactive energy, energy does not lose across the inductor, so the final energy of the circuit will be equal to the initial energy of the system.

So, the final energy of the circuit= 1.2 J