Question

A charged capacitor stores 10C at 40v its stored energy is

Answer 1

Answer:

8000

Explanation:

E=1/2CV2                                                                                                                            1/2×10×40×40 = 8000

Answer 2

Concept:

When a capacitor is completely charged, a potential difference (p.d.) exists between its plates, and the bigger the area of the plates and/or the smaller the distance between them (known as separation), the higher the charge that the capacitor can carry and the greater the Capacitance.

For a capacitor with a given capacitance in Farads, the capacitor's ability to hold this electrical charge (Q) between its plates is proportional to the applied voltage, V.

Find:

The stored energy in the capacitor.

Solution:

$Q=CV\\10=C*40\\C=\frac{1}{4}$

$Energy = \frac{1}{2}CV^2\\ Energy = \frac{1}{2}*\frac{1}{4}*(40)^2\\\\Energy = 200J$

Hence, the energy stored in the capacitor is $200J$.

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