Question

A charged oil drop is suspended in uniform field of 3 ×× 104 V m-1so that it neither falls nor rises. The charge on the drop will be : (take the mass of the charge 9.9 ×× 10-15 kg and g =10 ms-2)​

Answer 1

Answer:

Step-by-step explanation:

                   in electric field if that doesnt move then it is in equilibrium

                  i.e, mg = Eq

        now solve it u will surely get it mate......

                     let me know if u could.............

   

Answer 2

Answer:

Finesh

Ab batao ki tumhy notes clearly samaj to ay.