Question

A charged oil drop remain stationary when situated between two parallel plates 20 mm apart and a p.d. of 500V is applied to the plates. Find the charge on the drop if it has mass of 2×10^-4 kg.

Answer 1

Explanation:

Given A charged oil drop remain stationary when situated between two parallel plates 20 mm apart and a p.d. of 500 V is applied to the plates. Find the charge on the drop if it has mass of 2×10^-4 kg.

• Given a charged oil drop remains stationary between 2 parallel plates 20 mm apart.
• Now Electric field between plates will be E = V / r
•                                                                            = 500 / 20 mm  
•                                                                  = 500 / 0.020 (1 mm = 0.001 m)
•                                                                                = 25,000 V/m
• In equilibrium
• F = mg
• Or qE = 2 x 10^-4 x 10 (taking g = 10 m/s^2)
• Or qE = 20 x 10^-4
• Or q = 20 x 10^-4 / 25,000
• Or q = 8 x 10 ^-8 C
• Reference link will be
• https://brainly.in/question/9026404

Answer 2

Given;

Explanation:

distance (d) = 20mm