Question

a charged particle enters a magnetic field at right angles to the magnetic field . the field exists for a length equal to 1.5 times the radius of circular path of the particle . the particle will be deviated frm its path by

1. 90 deg

2. 1/ sin (2/3)

3. 30 deg

4. 180 deg

correct ans is 180deg Why????

Answer 1

Let magnetic field strength = B, charge = q, mass = m, r = radius of the circular path