Physics, asked by anna99, 1 year ago

A charged particle enters a magnetie diela
velocity v in a direction perpendicular to the
field. Find an expression for de cadius of the
circular path of the particle.

Answers

Answered by harsharora111
0

Answer:

fmagnetic force = fcentripetal

qvB = mv2/R

  • R= mv/qB
  • R= p/qB (p=momentum)
  • R= 2mE/qB
  • R= 2mqV/qB
  • where V= potential E = Electric Field

Thanks for Reading

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