A charged particle enters a magnetie diela
velocity v in a direction perpendicular to the
field. Find an expression for de cadius of the
circular path of the particle.
Answers
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0
Answer:
fmagnetic force = fcentripetal
qvB = mv2/R
- R= mv/qB
- R= p/qB (p=momentum)
- R= √2mE/qB
- R= √2mqV/qB
- where V= potential E = Electric Field
Thanks for Reading
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